How do you solve #abs( 4 - 2/7x )+ 2 = 14#?

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Answer 1 · 2015-09-01T13:01:28

#color(green)( x = -28 or x = 56#

#abs( 4 - 2/7x )+ 2 = 14#

Transposing #2# to the other side, we get:

#abs( 4 - 2/7x ) = 14 - 2#

#abs( 4 - 2/7x ) = 12#

This implies that :

#4 - 2/7x = 12 or 4 - 2/7x = -12 #

#- 2/7x = 12 - 4 or - 2/7x = -12 - 4 #

#- 2/7x = 8 or - 2/7x = -16 #

Multiplying both equations with #-7/2#, we get:

# x = 8*(-7/2) or x = -16*(-7/2) #

#color(green)( x = -28 or x = 56#