How do you graph x^2+y^2-6x-14y+42=0?

1 Answer
Sep 1, 2015

This formula describes a circle, which center is in O=(3,7) and radius is 4

Explanation:

To find this out you have to transform the formula to:

(x-a)^2+(y-b)^2=r^2.

In this formula a and b are coordinates of the center and r is the radius

x^2+y^2-6x-14y+42=0

(x^2-6x color(red)(+9)) +(y^2-14y color(red)(+49)) color(red)(-9-49) +42=0

(x-3)^2+(y-7)^2-16=0

(x-3)^2+(y-7)^2=16