How do you solve 4x - y = -5 and -2x + 3y = 10?
1 Answer
Explanation:
Your system of equations looks like this
#{(4x-y = -5), (-2x + 3y = 10):}#
Multiply the second equation by
#{(4x-y = -5), (-4x + 6y = 20):}#
Notice that if you add the left-hand side of the equations and the right-hand sides of the equations separately, you can eliminate the
This will allow you to find the value of
#{(4x-y = -5), (-4x + 6y = 20):}#
#stackrel("--------------------------------------------")#
#color(red)(cancel(color(black)(4x))) - y - color(red)(cancel(color(black)(4x))) + 6y = -5 + 20#
#5y = 15 implies y = color(green)(3)#
Now take the value of
#4x - 3 = -5#
#4x = -2 implies x = color(green)(-1/2)#