Question

How do you get sec 30?

Answer 1

`sec(30^@) = (2sqrt(3))/3`

Explanation:

`sec = 1/cos`

`30^@` is one of the "standard" angles

`cos(30^@) = ("adjacent")/("hypotenuse") = sqrt(3)/2`

`rArr sec(30^@) = 2/sqrt(3) = (2sqrt(3))/3`