Question

Question #12364

Answer 1

The carton has to be 104 mm long to hold 0.570 kg of skim milk.

Explanation:

To get this the following calculation was done:

Firstly convert 0.570 kg into grams

`0.570 kg*1000` = `570g`

Then divide the `570g` by the density of the skim milk to get the amount in `mL` that the milk will take up:

`(570g)/(1.031g/(mL))` = `552.86mL`

*The answer is in mL because the grams cancel each other out

Because `1g` = `1cm^3`, one can say:

`552.86mL` = `552.86cm^3`

Then the volume calculation can be done to find the length of the carton:

`V= w*b*l`

`552.86cm^3=7.3cm*7.3cm*l`

`552.86cm^3=53.29cm^2*l`

Therefore `l` equals:

`l` = `(552.86cm^3)/(53.29cm^2)`

  = #10.375 cm#
  = #103.75 mm#
  = #104mm#

Your question said the answer must be in two significant figures but in this case the answer is already three significant figures, so in two significant figures it would be `10*10^1mm` which isn't suitable in this case because that is equal to `100mm` and `0.570kg` won't fit into that size carton.

Therefore final answer for your length of carton is `104mm`.

Hope I helped :)