Question

How do you find the end behavior of `f(x) = (x-1)(x+2)(x+3)`?

Answer 1

See explanation

Explanation:

Expanding it gives us

`f(x)=x^3+4x^2+x-6=>f(x)=x^3*(1+4/x+1/x^2-6/x^3)`

Hence `f(x)->+oo` when `x->+oo`

and `f(x)->-oo` when `x->-oo`