Question

How do you condense `2log_3 6 - log_3 4`?

Answer 1

`2 log_3 6 - log_3 4 = 2`

Explanation:

Use `log_a b + log_a c = log_a (bc)`

and `log_a (1/b) = -log_a b`

`2 log_3 6 - log_3 4 = log_3 6^2 - log_3 4 = log_3 (36 / 4)`

`= log_3 9 = log_3 3^2 = 2`