How do you simplify #(3x+12)/(x+4)#?

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Answer 1 · 2015-09-23T16:23:15

#=color(blue)(3#

#(3x+12) / (x+4#

The expression #3x+12 # has #3 # common between both the terms:

So,
#3x+12 = color(blue)(3(x+4)#

The expression now becomes:

#(3x+12) / (x+4 )= color(blue)(3(x+4))/(x+4)#

#x+4# is common to both the numerator and denominator here.

# = color(blue)(3(cancel(x+4)))/(cancel(x+4)#

#=color(blue)(3#