Question

How do you differentiate `f(x) = 1 + 1/x + 7/x^2 + 1/x^3`?

Answer 1

Have a look:

Explanation:

You can write your function, using the Rule of Exponents, as:
`f(x)=1+x^-1+7x^-2+x^-3`

and differentiate as `x^n` which gives you `nx^(n-1)`, to get:

`(df)/dx=0-x^-2-14x^-3-3x^-4=-1/x^2-14/x^3-3/x^4`