Question

How do you differentiate `y=3x^4-6x^3+x^2/8+5`?

Answer 1

`(dy)/(dx)=12x^3-18x^2+x/4`

Explanation:

This is achieved by using the method;

if `y=ax^n`
then `dy/dx=nax^(n-1)`

Hope this helps :)