How do you simplify #((1/x) - (1/5))/((1/x^2) - (1/25))#? Algebra Rational Equations and Functions Division of Rational Expressions 1 Answer İnci Sep 27, 2015 According to the rule : #a^2-b^2 = (a-b)(a+b)# Explanation: #((1/x-1/5))/((1/x-1/5)(1/x+1/5))# #=cancel((1/x-1/5))/cancel((1/x-1/5))1/((1/x+1/5))# #=1/((x+5)/(5x)# #=5x/(x+5)# Answer link Related questions What is Division of Rational Expressions? How does the division of rational expressions differ from the multiplication of rational expressions? How do you divide 3 rational expressions? How do you divide rational expressions? How do you divide and simplify #\frac{9x^2-4}{2x-2} -: \frac{21x^2-2x-8}{1} #? How do you divide and reduce the expression to the lowest terms #2xy \-: \frac{2x^2}{y}#? How do you divide #\frac{x^2-25}{x+3} \-: (x-5)#? How do you divide #\frac{a^2+2ab+b^2}{ab^2-a^2b} \-: (a+b)#? How do you simplify #(w^2+6w+5)/(w+5)#? How do you simplify #(x^4-256)/(x-4)#? See all questions in Division of Rational Expressions Impact of this question 4363 views around the world You can reuse this answer Creative Commons License