How do you write the equation of the line parallel to 4x + 3y = 9 and passing through the point ( -10, 3 )?

1 Answer
Sep 27, 2015

4x+3y=-31

Explanation:

we know,
if a line is in general form Ax+By=C then the slope is m=-A/B
and parallel lines have the same slope.
so for the given equation,the slope is
m= - 4/3
The new line has slope -4/3 and contains the point (-10,3).
the general equation of line (where points and slope are given) is

y-y_"1" = m(x-x_"1");
So the equation will be
y-3= - 4/3(x+10)
after simplifying
4x+3y=-31