How do you factor #2x^2 + 14x - 16#?

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Answer 1 · 2015-09-28T01:46:19

#2x^2+14x-16=(2x-2)(x+8)#

First you factorise the entire polynomial by 2
#2(x^2+7x-8)#

Then, you would like to find two numbers that add together to give #+7# and multiply together to give #-8#.

You will find these two numbers are +8 and -1.

Use that information to factorise the expression.
#2(x-1)(x+8)#

Finally, Multiply the 2 back into one of the brackets.

#(2x-2)(x+8)#

Hope that helps

Answer 2 · 2015-09-28T01:51:48

#2x^2+14x-16=color(red)(2(x-1)(x+8))#

#2x^2+14x-16#

Factor out the GCF #2#.

#2(x^2+7x-8)#

Factor #(x^2+7x-8)#.

Find two numbers that when added equal #7# and when multiplied equal #-8#. The numbers #-1# and #8# fit the criteria.

#(x^2+7x-8)=color(red)((x-1)color(red)((x+8)#

#2x^2+14x-16=color(red)(2(x-1)(x+8))#