Question

How do you find the point on the unit circle that corresponds to pi/4?

Answer 1

`P(sqrt(2)/2,sqrt(2)/2)`

Explanation:

In the unit circle, all points are of the form `(cos(theta),sin(theta))` where `theta` is the angle made with the x-axis on the first quadrant, which, in this case is `pi/4` radians, or `(180º)/4 = 45º`

So now we just take the cosine, and the sine. Since `45º` is a special angle, we already know those values, and can just say

`P(sqrt(2)/2,sqrt(2)/2)`