How do you find the 6 trigonometric functions for 3pi/2? Trigonometry Right Triangles Trigonometric Functions of Any Angle 1 Answer Chandra S. Oct 1, 2015 3π2 = 2π - π2 . Sin [ 2π - π2] = - sinπ2 = -1 cos[2π - π2] = cosπ2 = 0. tan[2π - π2] = - tan π2 = -1/0 (undefined). Explanation: csc 3π2 = - 1, sec3π2 = 1/0 (undefined) and cot 3π2 = 0. Answer link Related questions How do you find the trigonometric functions of any angle? What is the reference angle? How do you use the ordered pairs on a unit circle to evaluate a trigonometric function of any angle? What is the reference angle for 140∘? How do you find the value of cot300∘? What is the value of sin−45∘? How do you find the trigonometric functions of values that are greater than 360∘? How do you use the reference angles to find sin210cos330−tan135? How do you know if sin30=sin150? How do you show that (cosθ)(secθ)=1 if θ=π4? See all questions in Trigonometric Functions of Any Angle Impact of this question 24530 views around the world You can reuse this answer Creative Commons License