Question

How do you find the 6 trigonometric functions for 3pi/2?

Answer 1

`3pi/2` = 2`pi` - `pi/2` . Sin [ 2`pi` - `pi/2`] = - sin`pi/2` = -1
cos[2`pi` - `pi/2`] = cos`pi/2` = 0.
tan[2`pi` - `pi/2`] = - tan `pi/2` = -1/0 (undefined).

Explanation:

csc `3pi/2` = - 1, sec`3pi/2` = 1/0 (undefined) and cot `3pi/2` = 0.