How do you solve $- 2 (y - 5) = 27$ $-2(y-5) = 27$ ?

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Answer 1 · 2015-10-02T11:22:44

$y = - \frac{17}{2}$ $color(blue)(y=-17/2$

$- 2 (y - 5) = 27$ $−2(y−5)=27$

$- 2 y + 10 = 27$ $−2y +10=27$

$- 2 y = 27 - 10$ $−2y =27 -10$

$- 2 y = 17$ $−2y =17$

$y = - \frac{17}{2}$ $color(blue)(y=-17/2$

How do you solve -2(y-5) = 27−2(y−5)=27-2(y-5) = 27?