Question

How do you find two solutions (in degree and radians) for `cot = -sqrt3`?

Answer 1

Solve `cot x = -sqrt3` in degree and radians

Ans: `x = 150^@; 330^@`

Explanation:

Trig Table of Special Arcs gives __>
`cot x = -sqrt3` --> arc `x = ((5pi)/6)` and `x = ((11pi)/6)`
In Deg --> `x = 150^@` and `x = 330^@`