Question

How do you differentiate `f(x) = sin ( x² ln(x) )`?

Answer 1

`(df(x))/dx = x(2lnx+1)cos(x^2lnx)`

Explanation:

`(df(x))/dx = d/dx(sin(x^2lnx))=cos(x^2lnx)*(2xlnx+x^2 1/x)`

`(df(x))/dx = x(2lnx+1)cos(x^2lnx)`