How do you find two solutions (in degree and radians) for #secx = sqrt2#?
1 Answer
Oct 13, 2015
The two solutions in degrees (from 0 to 360) would be 45 and 315.
In radians (from 0 to
Explanation:
#sec(x) = 1/cos(x)#
Plug in our givens:
#sqrt(2) = 1/cos(x)#
#cos(x) = 1/sqrt(2)#
#cos(x) = sqrt(2)/2#
Using the unit circle, I know that
We also know that the value at