How do you solve $(x-6)^2 = 25$ ?

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Answer 1 · 2015-10-14T20:11:59

$x=1$ or $x=11$

Rewriting $(x-6)^2=25$
as
$(x-6)^2-5^2=0$

we see the left side is the difference of squares with factors:
$((x-6)+5)*((x-6)-5) = 0$

Either
${: (,(x-6)+5 = 0, ," or ",,(x-6)-5=0), (rArr,x-1=0, , , ,x-11=0), (rArr,x=1, ," or ", ,x=11) :}$

How do you solve (x-6)^2 = 25 (x-6)^2 = 25?