How do you solve #5(1+10^6x) = 12#?

1 Answer
Oct 18, 2015

Rearrange and take logs if necessary to find #x#.

Explanation:

I'm not sure whether your question appears as intended, so I will answer both interpretations:

#bb (5(1+10^6x) = 12)#

Divide both sides by #5# to get:

#1+10^6x = 12/5#

Subtract #1# from both sides to get:

#10^6x = 7/5#

Divide both sides by #10^6# to get:

#x = 7/(5*10^6) = 0.0000014#

#bb (5(1+10^(6x)) = 12)#

Divide both sides by #5# to get:

#1+10^(6x) = 12/5#

Subtract #1# from both sides to get:

#10^(6x) = 7/5#

Take common logarithms of both sides to get:

#6x = log(7/5)#

Divide both sides by #6# to get:

#x = log(7/5)/6 ~~ 0.02435#