Question

How do you differentiate `(4x^-2) - 8x + 1`?

Answer 1

`y'=-8x^-3-8`

Explanation:

`y'=4(x^-2)'-8(x)'+(1)' = 4*(-2)*x^(-2-1) - 8*1 + 0`

`y'=-8x^-3-8`