Question

How do you evaluate `int (-1/(3x)) dx` for [1/11, 1/5]?

Answer 1

`0,26282`

Explanation:

`int_(1/11)^(1/5)-1/(3x)dx=-1/3int_(1/11)^(1/5)1/xdx`

`=1/3[ln|x|]_(1/11)^(1/5)`

`=1/3[ln(1/5)-ln(1/11)]`

`=0,26282`