Question

How do you differentiate `(y+3x)^2-4x=0`?

Answer 1

Assuming that we want `dy/dx`, we get:

`2(y+3x)d/dx(y+3x) - 4 = 0`

`2(y+3x)(dy/dx+3) - 4 = 0`

Now solve for `dy/dx`

`dy/dx = 2/(y+3x) -3`

Rewrite using algebra until you like the way it looks.