Question

How do you rewrite `(7ab^-2)/(3x)` using a positive exponent?

Answer 1

`(7ab^(-2))/(3x) = (7a)/(3b^2x)`

Explanation:

`b^3 = b xx b xx b`

`b^2 = b^3/b = b xx b`

`b^1 = b^2/b = b`

`b^0 = b^1/b = 1`

`b^(-1) = b^0/b = 1/b`

`b^(-2) = b^(-1)/b = (1/b)/b = 1/b^2`

And in other news:
`(7ab^(-2))/(3x) = (7a)/(3x) * b^(-2)`

`color(white)("XXXX") = (7a)/(3x)*1/b^2`

`color(white)("XXXX") = (7a)/(3xb^2)`