Question

How do you write the equation of a line with passes through (-1, 3) and (-6, -7) in standard from?

Answer 1

`2x-y=-5`

Explanation:

From the given, we can use two-point slope form

`(y-y_1)=(y_2-y_1)/(x_2-x_1)(x-x_1)`

`y-3=(-7-3)/(-6--1)(x--1)`

`y-3=(-10)/-5(x+1)`

`y-3=2(x+1)`

`y-3=2x+2`

`-2x+y=2+3`

`-1[-2x+y=5]-1`

`2x-y=-5` `rarr` standard form

`2x-y+5=0` `rarr` general form