What are the solutions of x^2-3x=-10?

2 Answers
Oct 22, 2015

The solutions are 3/2 pm i *sqrt(31)/2, where i=sqrt{-1} is the imaginary unit.

Explanation:

Write the equation in the form a x^2 +bx + c=0: x^2-3x=-10 implies x^2-3x+10=0.

The solutions, by the quadratic formula, are then:

x=(-b pm sqrt(b^2-4ac))/(2a)=(3 pm sqrt(9-4*1*10))/(2*1)

=(3 pm sqrt(-31))/2 = 3/2 pm i *sqrt(31)/2, where i=sqrt{-1} is the imaginary unit.

Oct 22, 2015

Imaginary numbers

Explanation:

=x^2-3x+10=0
graph{x^2-3x+10 [-23.11, 34.1, -3.08, 25.54]}
Using --- (b+ or - sqrt(b^2-4ac) )/ 2a

You'll see that it has complex roots, so by plotting a graph you can figure out the answer, but in the form

=
1.5 + 2.78388i
1.5 - 2.78388i