Question

What are the zero(s) of: `9 = 15t - 4.9t^2`?

Answer 1

`x~~0.82, 2.24`

Explanation:

To use the quadratic formula, lets first re-arrange the equation.
`-4.9t^2+15t-9`
Now use the quadratic formula
`(-15+-sqrt(15^2-4(-4.9)(9)))/(2(-4.9))`
Now we get
`(-15+-sqrt(48.6))/(2(-4.9)`

So `x~~0.82, 2.24`