Question

Question #6626e

Answer 1

`-28^@"C"`

Explanation:

To go from temperature expressed in degrees Celsius, `^@"C"`, to temperature expressed in Kelvin, `"K"`, you need the following conversion factor

`"t K" = "t"^@"C" + 273.15`

In simple terms, the origin of the Kelvin scale, `"0 K"`, also called absolute zero, is set at `-273.15^@"C"`. Temperatures expressed in Kelvin cannot be lower than `"0 K"`, so always make sure that you don't have negative temperatures in Kelvin.

Now, since you can go from degrees Celsiu to Kelvin by adding `273.15`, it follows that you can go from Kelvin to degrees Celsius by subtracting `273.15`

`"t"^@"C" = "t K" - 273.15`

In your case, a temperature of `"245 K"` would correspond to

`"t"[""^@"C"] = "245 K" - 273.15 = -28.15^@"C"`

You need to round this off to

`"t"[""^@"C"] = color(green)(-28^@"C")`