Question

How do you find the x and y intercept given `2x-3y-12=0`?

Answer 1

`x`-intercept: `(6,0)`
`y`-intercept: `(0,-4)`

Explanation:

The `x`-intercept is where the graph crosses the `x` axis, which is where `y=0`. Similarly, the `y`-intercept is where the graph crosses the `y` axis, or where `x=0`.

To find the intercept points, plug in `0` for either `x` or `y` and solve for the other. Lets start with the `x`-intercept.

`2x-3(0)-12 = 0`

Add `12` to both sides.

`2x=12`

Divide both sides by `2`.

`x=6`

So the ordered pair for the `x`-intercept is;

`(6,0)`

Now do the same with the `y`-intercept.

`2(0)-3y-12=0`

Again, add `12` to each side.

`-3y=12`

This time divide by `-3`.

`y=-4`

So the ordered pair for the `y`-intercept is;

`(0,-4)`