How do you solve #(x - 3 )^2 = -10#?
1 Answer
Oct 27, 2015
Explanation:
#(x-3)^2=-10#
#implies x-3 = sqrt(10)i#
#implies x= 2+sqrt(10)i #
#(x-3)^2=-10#
#implies x-3 = sqrt(10)i#
#implies x= 2+sqrt(10)i #