How do you solve (4x-1)^2= 16? Algebra Quadratic Equations and Functions Comparing Methods for Solving Quadratics 1 Answer Babette Oct 29, 2015 x=-3/4 and x=5/4 Explanation: Take the square root of both sides sqrt((4x-1)^2)=+-sqrt(16) 4x-1=+-4 So we need to solve 4x-1=4 and 4x-1=-4 4x=5 x=5/4 4x=-3 x=-3/4 Answer link Related questions What are the different methods for solving quadratic equations? What would be the best method to solve -3x^2+12x+1=0? How do you solve -4x^2+4x=9? What are the two numbers if the product of two consecutive integers is 72? Which method do you use to solve the quadratic equation 81x^2+1=0? How do you solve -4x^2+4000x=0? How do you solve for x in x^2-6x+4=0? How do you solve x^2-6x-16=0 by factoring? How do you solve by factoring and using the principle of zero products x^2 + 7x + 6 = 0? How do you solve x^2=2x? See all questions in Comparing Methods for Solving Quadratics Impact of this question 2768 views around the world You can reuse this answer Creative Commons License