How do you differentiate #f(x)=sin(6x+5x^2+1)# using the chain rule? Calculus Basic Differentiation Rules Chain Rule 1 Answer GiĆ³ Oct 29, 2015 I found: #f'(x)=(10x+6)cos(6x+5x^2+1)# Explanation: First you derive #sin# as it is and then multiply by the derivative of its argument: #f'(x)=color(red)(cos(6x+5x^2+1))*color(blue)((6+10x))=# #=(10x+6)cos(6x+5x^2+1)# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 1535 views around the world You can reuse this answer Creative Commons License