How do you find the exact value of #tan(theta) = -4#?

1 Answer
Oct 30, 2015

#theta = {(-1.32586 +-npi " radians"),("or"),(-75.9638^@ +- n*180^@):}#
#AAn in ZZ#

Explanation:

#tan(theta)=-4# is not descriptive of any of the standard triangles so the best we can do is use a calculator:
#theta = arctan(tan(theta)) = arctan(-4) = -1.32582# (radians)

Since #tan(x) = tan(x+pi)#
adding any integer multiple of #pi# to #theta# will give the same value for #tan(theta)# and are therefore also valid solutions.

#-1.32582 " radians" = -75.9638^@#

Note that these values are not "exact" (as requested in the question) but they are quite accurate and the best I can see how to determine.