Question

How do you find the definite integral of `int (3x-x^2)dx` from `[1,3]`?

Answer 1

`10/3`

Explanation:

Use laws of integration to write the anti-derivative, and then use the Fundamental Theorem of Calculus to evaluate it between the limits given.

`int_1^3(3x-x^2)dx=[3x^2/2-x^3/3]_1^3`

`=(27/2-27/3)-(3/2-1/3)`

`=10/3`