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How do you solve $x^{2} + 17 = 0$ $x^2 + 17 = 0$ ?

1 Answer

Nov 2, 2015

No real roots

Explanation:

This can be written as

$x^{2} = - 17$ $x^2 = -17$

$x = \pm \sqrt{- 17}$ $x = +-sqrt(-17)$

Well you have 2 possible complex root but they are real

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