How do you solve #log_(2) (5x + 7) - log_(2) x = 2#?
1 Answer
Nov 2, 2015
Explanation:
Note that
#log_2 (5x+7)- log_2 x =2#
#implieslog_2 (5x+7)+ log_2 (1/x)=2#
#implies log_2((5x+7)/x)=2#
#implies (5x+7)/(x)= 2^2#
#implies 5x+7 =4x#
#implies x = -7#
