Question

What are the six trig function values of `-405`?

Answer 1

Find the trig function ratio of (-405)

Explanation:

`sin (-405) = sin (-45 - 360) = sin (-45) = - sin 45 = - sqrt2/2`
`cos (-405) = cos (-45 - 360) = cos (-45) = cos 45 = sqrt2/2`
`tan (-405) = sin/(cos) = -1`
`cot (-405) = -1`
`sec (-405) = 1/(cos) = 2/sqrt2 = (2sqrt2)/2 = sqrt2`
`csc (-405) = 1/(sin) = -2/sqrt2 = - (2sqrt2)/2 = - sqrt2`