Hoe do you differentiate #f(x)=ln(1/x) #? Calculus Differentiating Logarithmic Functions Differentiating Logarithmic Functions with Base e 1 Answer Konstantinos Michailidis Nov 3, 2015 It is #f(x)=ln(1/x)=>d/dxf(x)=(d/dx(1/x))/(1/x)=>f'(x)=-1/x# Remember that if #f(x)=lng(x)# then #f'(x)=(g'(x))/g(x)# Answer link Related questions What is the derivative of #f(x)=ln(g(x))# ? What is the derivative of #f(x)=ln(x^2+x)# ? What is the derivative of #f(x)=ln(e^x+3)# ? What is the derivative of #f(x)=x*ln(x)# ? What is the derivative of #f(x)=e^(4x)*ln(1-x)# ? What is the derivative of #f(x)=ln(x)/x# ? What is the derivative of #f(x)=ln(cos(x))# ? What is the derivative of #f(x)=ln(tan(x))# ? What is the derivative of #f(x)=sqrt(1+ln(x)# ? What is the derivative of #f(x)=(ln(x))^2# ? See all questions in Differentiating Logarithmic Functions with Base e Impact of this question 2236 views around the world You can reuse this answer Creative Commons License