How do you find the average rate of change of #y= -3(x-4)^2+3# over interval [-4,9]?

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Answer 1 · 2015-11-05T05:45:40

#9#

average rate of change : #(f(b)-f(a))/(b-a)#

#b = 9#
#a=-4#

#((-3(9-4)^2+3)-(-3(-4-4)^2+3))/(9-(-4))#

#((-3(5)^2+3)-(-3(-8)^2+3))/(13)#

#((-3(25)+3)-(-3(64)+3))/(13)#

#((-72)-(-189))/(13)#

#9#