How would you determine the oxidation number for sodium sulfate?

1 Answer
anor277
Nov 6, 2015

Oxygen assumes its usual oxidation state of #-II#. Therefore, #S# here has its maximum oxidation number of #VI^+#.

Explanation:

Sum up the oxidation numbers: #4xx(-II) + S_(ON) = 2^-#, the charge on anion. Therefore, #S_(ON) = ??# How would you determine the oxidation numbers of the sulfurs in thiosulfate anion, #S_2O_3^(2-)#?

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