Question

How do you integrate `int x/(x-6) dx` using partial fractions?

Answer 1

Don't need to use partial fractions.

Explanation:

Step 1: divide `(x-6)` into `x` using long division:

`x/(x-6)=1+6/(x-6)`

Step 2: Integrate

`int[1+6/(x-6)]dx=x+6ln(x-6)+C`

hope that helped