How do you find the value of tan^-1[tan(3pi/5)]tan1[tan(3π5)]?

1 Answer
Nov 15, 2015

tan^(-1) (tan(3 pi/5)) =3 pi/5tan1(tan(3π5))=3π5
see explanation.

Explanation:

arctan " or " tan^(-1)arctan or tan1 are both the same thing.

Tangent is the numeric value you obtain if you have ("opposite")/("adjacent")oppositeadjacent for a right triangle. In other words the amount of 'up' for 1 'along'. It is the gradient value of the hypotenuse

Ok! we have now established what a tangent is so what is tan^(-1)tan1? Put simply it is the process of reversing the numeric tangent value back into the angle between the hypotenuse and the adjacent.

tan(3 pi/5)tan(3π5) converts the angle of 3 pi/53π5 into the gradient.

tan^(-1) " of " tan(3 pi/5)tan1 of tan(3π5) reverses the process. So if you have
tan^(-1)(tan("something")tan1(tan(something) the tan^(-1)(tan()tan1(tan() cancel each other out and you are left with just the angle that you started with.

so tan^(-1) (tan(3 pi/5)) =3 pi/5tan1(tan(3π5))=3π5