Question #49fdc

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Question #49fdc

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Answer 1 · 2015-11-16T16:11:07

See explanation.

Explanation:

I am not sure why the answer is missing a very essential point which is teaching the student Le Châtelier's principle . Maybe this is not a grade 12 question!!!!

The student could easily deduce that since the $[I_{2}] = 0 M$ $[I_2]=0M$ the equilibrium will shift toward the direction of making $I_{2}$ $I_2$ and therefore to the left and in this case, the ICE table is written as follows:

$H_{2} (g) + I_{2} (g) ⇌ 2 H I (g)$ $" " " " " " " " " "H_2(g)+I_2(g)rightleftharpoons 2HI(g)$
$I n i t i a l 8 M 0M 2.4 M$ $Initial" " " " " "8M" " "0M" " " " "2.4M$
$Change + x +x - 2 x$ $"Change" " " " " " "+x" +x" " " " "-2x$
$E q u i l i b r i u m 8 + x x 2.4 - 2 x$ $Equilibrium" "8+x" " x" " " "2.4-2x$

In this case, ONLY $positive$ $color(green)("positive")$ values of $x$ $x$ will be accepted.

However, the way the answer is written is that he will assume that the equilibrium is shifting to the right and in this case $x$ $x$ will be $positive$ $color(green)("positive")$ , however, if his assumption is wrong, $x$ $x$ will be $negative$ $color(red)("negative")$ and this is the case, that is why the $[H I]$ $[HI]$ dropped from $2.4 M$ $2.4M$ to $2.2 M$ $2.2M$ .

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Question #49fdc

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