How would you balance Ag2O --> Ag + O2?

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How would you balance Ag2O --> Ag + O2?

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Answer 1 · 2015-11-18T13:40:43

$2 A g_{2} O \to 4 A g + O_{2}$ $2Ag_2O-> 4Ag + O_2$

Explanation:

How to balance?
We have an equation;
$A g_{2} O \to A g + O_{2}$ $Ag_2O -> Ag + O_2$
First of all balance the O on both sides, now look at the product side. We have 2 oxygen on right side and on left side we have only 1 oxygen. To balance it, put a coefficient 2 on left side before $A g_{2} O$ $Ag_2O$ . The equation becomes as
$2 A g_{2} O \to A g + O_{2}$ $2Ag_2O -> Ag + O_2$
Now again check the product side, There is 1 Ag but in reactant side there is 4 Ag. Now put coefficient 4 before Ag on right side. The equation becomes as;
$2 A g_{2} O \to 4 A g + O_{2}$ $2Ag_2O-> 4Ag + O_2$

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How would you balance Ag2O --> Ag + O2?

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