Question

How do you solve `logx = 3`?

Answer 1

`x=1000`

Explanation:

Note that when `log` is not paired with a base, there base is implied to be `10`. So, `logx` can be written as `log_10x`.

`log_10x=3`

`10^(log_10x)=10^3`

`x=1000`