How do you evaluate cot(210) ? Trigonometry Right Triangles Trigonometric Functions of Any Angle 1 Answer Konstantinos Michailidis Nov 21, 2015 We have that #sin 210 = sin (30 + 180) = -sin 30 = -1/2# #cos 210 = cos (30 + 180) = -cos 30 = (-sqrt3)/2# #cot 210 = cos 210/sin 210 = [(-sqrt3)/2]:(-1/2) = sqrt3# Answer link Related questions How do you find the trigonometric functions of any angle? What is the reference angle? How do you use the ordered pairs on a unit circle to evaluate a trigonometric function of any angle? What is the reference angle for #140^\circ#? How do you find the value of #cot 300^@#? What is the value of #sin -45^@#? How do you find the trigonometric functions of values that are greater than #360^@#? How do you use the reference angles to find #sin210cos330-tan 135#? How do you know if #sin 30 = sin 150#? How do you show that #(costheta)(sectheta) = 1# if #theta=pi/4#? See all questions in Trigonometric Functions of Any Angle Impact of this question 2172 views around the world You can reuse this answer Creative Commons License