How do you factor the trinomial # 49 - 4x^2#? Algebra Polynomials and Factoring Factorization of Quadratic Expressions 1 Answer Meave60 Nov 23, 2015 #7^2-(2x)^2=(7+2x)(7-2x)# Explanation: #49-4x^2# represents a difference of squares, in which #a^2-b^2=(a+b)(a-b)#, where #a=7 and b=2x#. #7^2-(2x)^2=(7+2x)(7-2x)# Answer link Related questions How do you factor trinomials? What is factorization of quadratic expressions? How do you factor quadratic equations with a coefficient? What are some examples of factoring quadratic expressions? How do you check that you factored a quadratic correctly? How do you factor #x^2+16x+48#? How do you factor #x^2-9x+20#? Question #3fdac How do you factor #8+z^6#? There is no GCF to be factor out, so is there another method to complete this? How do you factor #2t^2+7t+3#? See all questions in Factorization of Quadratic Expressions Impact of this question 1206 views around the world You can reuse this answer Creative Commons License