Question

How do you implicitly differentiate `22=(x)/(1-xe^y)`?

Answer 1

`dy/dx= - (1+22e^y)/(22xe^y)`

Explanation:

Using cross multiplication it is, `22-22xe^y =x`.
Now differentiate w.r.t x, `0-22 e^y -22x e^y dy/dx=1`

`dy/dx= - (1+22e^y)/(22xe^y)`