How do you solve #4x^2=3x#?

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Answer 1 · 2015-11-23T11:03:10

#x=0 ; color(white)(...) x=3/4#

Given: #4x^2=3x#

So #color(white)(.....)4x^2-3x=0#

#color(white)(..,,...)x(4x-3)=0#

In which case #x=0 or 4x-3=0#

Consider #4x-3=0 -> 4x=3#

So #x=3/4#

Solution: #x=0 ; color(white)(...) x=3/4#